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[转载]MySQL根据某一个或者多个字段查找重复数据的sql语句
1.表中有id和name 两个字段,查询出name重复的所有数据
1 | select * from xi a where (a.username) in (select username from xi group by username having count(*) > 1) |
2、查询出所有数据进行分组之后,和重复数据的重复次数的查询数据,先列下:
1 | select count(username) as '重复次数',username from xi group by username having count(*)>1 order by username desc |
3、一下为 查看别人的 结果,现列下:查询及删除重复记录的方法大全
1、查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断
1 2 | select * from people where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1) |
2、删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有rowid最小的记录
1 2 3 | delete from people where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1) and rowid not in (select min(rowid) from people group by peopleId having count(peopleId )>1) |
3、查找表中多余的重复记录(多个字段)
1 2 | select * from vitae a where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1) |
4、删除表中多余的重复记录(多个字段),只留有rowid最小的记录
1 2 3 | delete from vitae a where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1) and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1) |
5、查找表中多余的重复记录(多个字段),不包含rowid最小的记录
1 2 3 | select * from vitae a where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1) and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1) |
(二)
比方说
在A表中存在一个字段“name”,
而且不同记录之间的“name”值有可能会相同,
现在就是需要查询出在该表中的各记录之间,“name”值存在重复的项;
1 | Select Name,Count(*) From A Group By Name Having Count(*) > 1 |
如果还查性别也相同大则如下:
1 | Select Name,sex,Count(*) From A Group By Name,sex Having Count(*) > 1 |
(三)
方法一
1 2 3 4 5 6 7 8 9 10 11 | declare @max integer,@id integer declare cur_rows cursor local for select 主字段,count(*) from 表名 group by 主字段 having count(*) >; open cur_rows fetch cur_rows into @id,@maxwhile @@fetch_status=0 begin select @max = @max -1 set rowcount @max delete from 表名 where 主字段 = @id fetch cur_rows into @id,@maxend close cur_rows set rowcount 0 |
方法二"重复记录"有两个意义上的重复记录,一是完全重复的记录,也即所有字段均重复的记录,二是部分关键字段重复的记录,比如Name字段重复,而其他字段不一定重复或都重复可以忽略。
1、对于第一种重复,比较容易解决,使用
1 | select distinct * from tableName |
就可以得到无重复记录的结果集。
如果该表需要删除重复的记录(重复记录保留1条),
可以按以下方法删除
1 2 3 4 | select distinct * into #Tmp from tableName drop table tableName select * into tableName from #Tmp drop table #Tmp |
发生这种重复的原因是表设计不周产生的,增加唯一索引列即可解决。
2、这类重复问题通常要求保留重复记录中的第一条记录,操作方法如下 假设有重复的字段为Name,Address,要求得到这两个字段唯一的结果集
1 2 3 | select identity(int,1,1) as autoID, * into #Tmp from tableName select min(autoID) as autoID into #Tmp2 from #Tmp group by Name,autoID select * from #Tmp where autoID in(select autoID from #tmp2) |
最后一个select即得到了Name,Address不重复的结果集(但多了一个autoID字段,实际写时可以写在select子句中省去此列)
(四)查询重复
1 | select * from tablename where id in (select id from tablenamegroup by idhaving count(id) > 1) |
对一个字段查找重复记录
根据sample_code字段找到重复记录
1 | SELECT * FROM tb_table WHERE sample_code IN( SELECT sample_code FROM tb_table GROUP BY sample_code HAVING COUNT(sample_code) > 1 ); |
对多个字段查找重复记录(这里以2个为例)
根据name和code字段找到重复记录
1 2 3 4 | SELECT * from (SELECT *, CONCAT(name,code) as nameAndCode from tb_table) t WHERE t.nameAndCode in ( SELECT nameAndCode from (SELECT CONCAT(name,code) as nameAndCode from tb_table) tt GROUP BY nameAndCode HAVING count(nameAndCode) > 1 ) |
多字段查,删
查
SELECT * FROM vip_goodsdiscount WHERE (goodsId,cardType) IN (SELECT goodsId,cardType FROM vip_goodsdiscount GROUP BY goodsId,cardType HAVING COUNT(*) > 1)
ORDER BY goodsId DESC
删
DELETE FROM vip_goodsdiscount
WHERE (vip_goodsdiscount.goodsId,vip_goodsdiscount.cardType) IN (SELECT * FROM (SELECT goodsId,cardType FROM vip_goodsdiscount GROUP BY goodsId,cardType HAVING COUNT(*) > 1) AS t1 )
AND id NOT IN (SELECT * FROM (SELECT MIN(id) FROM vip_goodsdiscount GROUP BY goodsId,cardType HAVING COUNT(*)>1) AS t2)
form https://www.cnblogs.com/zhangzhiping35/p/12066930.html